{"id":18461,"date":"2024-02-21T09:18:09","date_gmt":"2024-02-21T09:18:09","guid":{"rendered":"https:\/\/soicau1008.minhngocxoso.com\/?p=18461"},"modified":"2024-02-21T09:18:09","modified_gmt":"2024-02-21T09:18:09","slug":"thuat-toan-du-doan-lo-to-mien-bac-hom-nay","status":"publish","type":"post","link":"https:\/\/soicaumb24.com\/thuat-toan-du-doan-lo-to-mien-bac-hom-nay\/","title":{"rendered":"Thu\u1eadt to\u00e1n d\u1ef1 \u0111o\u00e1n l\u00f4 t\u00f4 mi\u1ec1n B\u1eafc h\u00f4m nay"},"content":{"rendered":"

Thu\u1eadt to\u00e1n d\u1ef1 \u0111o\u00e1n l\u00f4 t\u00f4 mi\u1ec1n B\u1eafc h\u00f4m nay<\/span><\/p>\n

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May m\u1eafn c\u1ee7a b\u1ea1n \u0111\u01b0\u1ee3c bao l\u00e2u khi ch\u01a1i x\u1ed5 s\u1ed1? B\u1edfi v\u1eady c\u1ea7n d\u1ef1 \u0111o\u00e1n l\u00f4 t\u00f4 mi\u1ec1n B\u1eafc h\u00f4m nay<\/strong> \u0111\u1ec3 t\u0103ng th\u00eam c\u01a1 h\u1ed9i tr\u00fang th\u01b0\u1edfng. C\u00f9ng t\u00ecm hi\u1ec3u ngay c\u00e1ch t\u00ednh to\u00e1n d\u1ef1 \u0111o\u00e1n d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ec3 mang t\u00e0i l\u1ed9c v\u1ec1 nh\u00e0 nh\u00e9.<\/p>\n

D\u1ef1 \u0111o\u00e1n l\u00f4 t\u00f4 mi\u1ec1n B\u1eafc h\u00f4m nay qua gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/strong><\/h2>\n

Soi c\u1ea7u x\u1ed5 s\u1ed1, ta x\u00e9t k\u1ebft qu\u1ea3 trong 2 h\u00f4m tr\u01b0\u1edbc. Gi\u1ea3 s\u1eed ng\u00e0y th\u1ee9 nh\u1ea5t c\u00f3 2 s\u1ed1 cu\u1ed1i gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 58 -> ng\u00e0y th\u1ee9 3 s\u1ebd c\u00f3 36 ( v\u00ec 5->3 ; 6 )<\/p>\n

H\u00f4m nay th\u1ea5y c\u00f3 s\u1ed1 \u0110\u1ec1 v\u1ec1 32 ->ng\u00e0y kia d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong> s\u1ebd c\u00f3 l\u00f4 15 ( v\u00ec 3->1 ; 2->5)<\/p>\n

Tuy nhi\u00ean, c\u00e1ch t\u00ednh n\u00e0y ch\u1ec9 ch\u00ednh x\u00e1c v\u1edbi gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y 1 c\u00f3 t\u1ed5ng t\u1eeb 20 -> 30.<\/p>\n

T\u00ednh to\u00e1n c\u1ee5 th\u1ec3:<\/p>\n

Quy \u0111\u1ecbnh trong d\u1ef1 \u0111o\u00e1n l\u00f4 t\u00f4 mi\u1ec1n B\u1eafc h\u00f4m nay<\/strong>:<\/p>\n

MN = Con \u0110\u1ec1 v\u1ec1 ng\u00e0y 1<\/p>\n

CD = Con \u0110\u1ec1 v\u1ec1 ng\u00e0y 2<\/p>\n

AB = s\u1ed1 c\u1ea7n d\u1ef1 \u0111o\u00e1n (A, B l\u00e0 kh\u00e1c nhau trong 1 s\u1ed1)<\/p>\n

VD: MN = 35 ( 3#5) CD = 39 ( 3#9), c\u00f3 th\u1ec3 c\u00e1c s\u1ed1 MNCD c\u00f3 th\u1ec3 gi\u1ed1ng nhau nh\u01b0 M gi\u1ed1ng C<\/p>\n

Trong t\u1eebng ng\u00e0y ch\u01a1i c\u1ee5 th\u1ec3 ta c\u00f3:<\/p>\n

T\u1ed5ng trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t = 20 ; 25<\/p>\n

H\u00f4m th\u1ee9 1 c\u00f3 \u0110\u1ec1 = MN -> s\u1ed1 l\u00f4 ng\u00e0y c\u1ea7n d\u1ef1 \u0111o\u00e1n = AB => Ta \u0111\u00e1nh BA<\/p>\n

C\u00f3 t\u1ed5ng \u0111\u1eb7c bi\u1ec7t = s\u1ed1 ch\u1eb5n ( 22, 24, 26, 28)<\/p>\n

H\u00f4m th\u1ee9 1 \u0111\u1ec1 = MN -> ta d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong> L\u00f4 ng\u00e0y 3 = AB<\/p>\n

Ti\u1ebfp t\u1ee5c t\u00ednh to\u00e1n c\u00f4ng th\u1ee9c: 10 \u2013 B = I  v\u00e0 gi\u1eef nguy\u00ean A => ch\u1ed1t \u0111\u01b0\u1ee3c s\u1ed1 AI<\/p>\n

C\u00e1c t\u1ed5ng b\u1eb1ng s\u1ed1 l\u1ebb c\u00f3 30 (21, 23, 29, 30)<\/p>\n

H\u00f4m 1 \u0111\u1ec3 = MN -> d\u1ef1 \u0111o\u00e1n k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1<\/strong> ng\u00e0y 3 = AB => \u0111\u00e1nh AB<\/p>\n

\u0110\u1eb7c bi\u1ec7t l\u01b0u t\u00e2m khi ch\u01a1i s\u1ed1<\/h2>\n
\"C\u00e1ch
D\u1ef1 \u0111o\u00e1n l\u00f4 t\u00f4 mi\u1ec1n B\u1eafc h\u00f4m nay chu\u1ea9n x\u00e1c<\/figcaption><\/figure>\n

S\u1ed1 l\u00f4 trong ng\u00e0y 1 = MN -> suy ra l\u00f4 ng\u00e0y 3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong> l\u00e0 AB.<\/p>\n

S\u1ed1 l\u00f4 trong ng\u00e0y 2 l\u00e0 CD. M\u00e0 MN -> CD ( MN -> CD t\u01b0\u01a1ng t\u1ef1 MN-> AB)<\/p>\n

T\u1ee9c AB=CD ( k\u1ebft qu\u1ea3 ng\u00e0y 2 = v\u1edbi l\u00f4 d\u1ef1 t\u00ednh ng\u00e0y 3)<\/p>\n

=> BA l\u00e0 k\u1ebft qu\u1ea3 sau qu\u00e1 tr\u00ecnh t\u00ednh to\u00e1n soi l\u00f4<\/strong><\/p>\n

\u0110\u1ec1 ng\u00e0y 1 -> l\u00f4 ng\u00e0y 3 l\u00e0 AB. T\u1ed5ng ng\u00e0y 2 c\u00f3 \u0111\u01b0\u1ee3c = xy -> AB<\/p>\n

=> Ta \u0111\u00e1nh con BA<\/p>\n

VD: \u0110\u1ec1 ng\u00e0y 1 = 35 -> l\u00f4 ng\u00e0y 3 = 13. Nh\u01b0ng c\u00f3 t\u1ed5ng ng\u00e0y 2 c\u0169ng = 35 -> 13 => ng\u00e0y 3 \u0111\u00e1nh l\u00f4 31<\/p>\n

\u0110\u1ec1 ng\u00e0y 1 = MN -> d\u1ef1 \u0111o\u00e1n ng\u00e0y 3 = AB. \u0110\u1ec1 v\u1ec1 ng\u00e0y 2= CD. M\u00e0 C= M+x, D=N+x ( x l\u00e0 s\u1ed1 \u00e2m ho\u1eb7c d\u01b0\u01a1ng \u0111\u1ec1u \u0111\u00fang) => Ch\u1ed1t l\u1ef1a ch\u1ecdn BA<\/p>\n

Nh\u1eefng c\u00e1ch t\u00ednh to\u00e1n d\u1ef1 \u0111o\u00e1n l\u00f4 t\u00f4 mi\u1ec1n B\u1eafc h\u00f4m nay<\/strong> kh\u00f4ng qu\u00e1 ph\u1ee9c t\u1ea1p. M\u1ed9t ch\u00fat khoa h\u1ecdc t\u00ednh to\u00e1n, m\u1ed9t ch\u00fat may m\u1eafn l\u00e0 \u0111\u1ee7 \u0111\u1ec3 b\u1ea1n c\u00f3 th\u1ec3 tr\u00fang th\u01b0\u1edfng.<\/p>\n<\/div>\n<\/div>\n

ch\u1ed1t s\u1ed1 vip<\/h3>\n
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